Standardized vs Unstandardized Coefficients in R: When Each Matters

An unstandardized regression coefficient tells you how the response changes when a predictor moves by one raw unit (kg, dollars, years). A standardized coefficient tells the same story after every variable is rescaled to standard-deviation units, so predictors measured on different scales become directly comparable.

What's the difference between standardized and unstandardized coefficients?

A single lm() call on mtcars can tell two very different stories depending on whether we rescale the inputs. We fit the same model twice, once on raw data and once on standardized data, and watch the coefficients transform from "mpg per pound of weight" into "mpg-in-SD-units per weight-in-SD-units." Same data, same relationships, different units of interpretation.

RRaw vs standardized coefficients side by side
# Fit the raw model on mtcars fit_raw <- lm(mpg ~ wt + hp, data = mtcars) # Z-score every column, refit on the standardized data mtcars_z <- as.data.frame(scale(mtcars[, c("mpg", "wt", "hp")])) fit_std <- lm(mpg ~ wt + hp, data = mtcars_z) # Compare the two sets of coefficients data.frame( raw = round(coef(fit_raw), 3), standardized = round(coef(fit_std), 3) ) #> raw standardized #> (Intercept) 37.227 0.000 #> wt -3.878 -0.630 #> hp -0.032 -0.361

  

The raw model says each additional 1000 lb of weight lowers mpg by 3.88 units, and each additional horsepower lowers it by 0.032 units. Read literally, weight looks roughly 120 times more "important" than horsepower, which is a trick of the scale (weight is measured in thousands of pounds, horsepower in single units). The standardized model rescales both predictors to the same yardstick (one standard deviation), and the coefficients become -0.63 for weight and -0.36 for hp. Weight is still the stronger predictor, but only by a factor of about 1.75, not 120.

Key Insight
Coefficient magnitude is not importance; scale determines magnitude. A raw coefficient of 0.032 looks negligible, but if the predictor ranges across hundreds of units, its total contribution can dominate the model. Standardization removes this trap by putting every predictor on the same "per standard deviation" ruler.

Try it: Fit a simple regression of mpg on disp using mtcars and print the raw coefficient. Pay attention to how small the number is, even though disp (engine displacement in cubic inches) varies by hundreds of units across the dataset.

RYour turn: raw coefficient for disp
# Try it: fit mpg ~ disp on mtcars and print the raw slope ex_disp_fit <- lm(mpg ~ disp, data = mtcars) # your code here #> Expected: a slope near -0.04 (small number, but disp ranges ~70-470)

  
Click to reveal solution
RRaw disp coefficient solution
ex_disp_fit <- lm(mpg ~ disp, data = mtcars) round(coef(ex_disp_fit), 4) #> (Intercept) disp #> 29.5999 -0.0412

  

The slope is -0.0412. Each extra cubic inch of displacement knocks mpg down by 0.04 units, which sounds trivial, until you remember disp spans roughly 400 units from the smallest to largest engine in the dataset. That's a total swing of about 16 mpg, which is anything but trivial. This is exactly the trap standardization is designed to sidestep.

How do you compute standardized coefficients in R?

Two routes lead to the same numbers. The first route rescales the data then refits; the second route leaves the data alone and rescales the coefficients themselves. We will walk through both, because understanding the formula behind the shortcut makes the output interpretable rather than magical.

RStandardize with scale() and refit
# scale() centers and divides by SD for every numeric column mtcars_scaled <- as.data.frame(scale(mtcars)) # Refit the same model on the standardized data fit_scaled <- lm(mpg ~ wt + hp, data = mtcars_scaled) round(coef(fit_scaled), 4) #> (Intercept) wt hp #> 0.0000 -0.6296 -0.3612

  

The intercept collapses to zero, because after centering every variable has mean zero, so the regression line must pass through the origin. The slope for wt is -0.630 and for hp is -0.361. Those are our standardized coefficients. Note we standardized the response too; some tools standardize only predictors, which gives a "semi-standardized" coefficient that tells a slightly different story (see the pitfalls section).

How standardization rescales variables before fitting.

Figure 1: How each variable is z-scored before fitting, so betas come out in SD units.

The manual formula makes the transformation explicit. If $\beta_{\text{raw}}$ is the raw coefficient for predictor $x$, its standardized version is:

$$\beta_{\text{std}} = \beta_{\text{raw}} \times \frac{\text{SD}(x)}{\text{SD}(y)}$$

Where:

  • $\beta_{\text{raw}}$ is the unstandardized coefficient from lm() on raw data
  • $\text{SD}(x)$ is the standard deviation of the predictor
  • $\text{SD}(y)$ is the standard deviation of the response

We can verify this formula reproduces what scale() gave us.

RStandardize via the SD-ratio formula
# Start with raw coefficients raw_coef <- coef(fit_raw)[-1] # drop the intercept # Compute SDs from the raw data sd_y <- sd(mtcars$mpg) sd_x <- c(wt = sd(mtcars$wt), hp = sd(mtcars$hp)) # Multiply by SD(x) / SD(y) per predictor manual_std <- raw_coef * sd_x / sd_y round(manual_std, 4) #> wt hp #> -0.6296 -0.3612

  

Identical numbers. Now line them up next to scale() to confirm both approaches agree to numerical precision.

RConfirm scale() and manual formula match
compare_df <- data.frame( scale_route = round(coef(fit_scaled)[-1], 6), manual_route = round(manual_std, 6) ) compare_df #> scale_route manual_route #> wt -0.629571 -0.629571 #> hp -0.361236 -0.361236

  

Both routes produce the same standardized coefficients. For most analyses you will use scale() + lm(), but seeing the formula makes the output interpretable and debuggable.

Note
scale() returns a numeric matrix with center and scale attributes. To use it in lm() via a data = argument, wrap it in as.data.frame() or standardize one column at a time inside mutate(). The QuantPsyc::lm.beta() function in an external package gives the same coefficients directly from a raw lm object if you want a one-liner shortcut.

Try it: Compute the standardized coefficient for a simple regression of mpg on wt two ways: first by fitting lm(mpg ~ wt) on raw mtcars and applying the SD-ratio formula, then by refitting on scale(mtcars[, c("mpg", "wt")]). Check they agree.

RYour turn: simple regression manual standardization
# Try it: compute the standardized slope for mpg ~ wt two ways ex_wt_fit <- lm(mpg ~ wt, data = mtcars) # Manual formula route (fill in): # ex_wt_std_manual <- ... # scale() route (fill in): # ex_wt_std_scaled <- ... # your code here #> Expected: both numbers equal approximately -0.868

  
Click to reveal solution
RSimple regression standardization solution
ex_wt_fit <- lm(mpg ~ wt, data = mtcars) # Manual: raw slope times SD(wt) / SD(mpg) ex_wt_std_manual <- coef(ex_wt_fit)["wt"] * sd(mtcars$wt) / sd(mtcars$mpg) # scale() route ex_wt_scaled <- as.data.frame(scale(mtcars[, c("mpg", "wt")])) ex_wt_std_scaled <- coef(lm(mpg ~ wt, data = ex_wt_scaled))["wt"] c(manual = round(ex_wt_std_manual, 4), scaled = round(ex_wt_std_scaled, 4)) #> manual.wt scaled.wt #> -0.8677 -0.8677

  

Both approaches land on -0.8677. In a simple regression the standardized slope equals the Pearson correlation between predictor and response, because there is no other predictor to adjust for. Verify with cor(mtcars$mpg, mtcars$wt) and you'll see the same number.

When should you use standardized vs unstandardized coefficients?

The choice is not about which number is "correct" (both are mathematically valid) but about which question you are answering. Three guiding questions decide it for almost every analysis.

Decision flowchart: which coefficient to report.

Figure 2: Pick the coefficient type that matches your goal: prediction, importance, or communication.

Report unstandardized coefficients when you:

  1. Need to predict a response in its original units (a patient's blood pressure in mmHg, a house price in dollars).
  2. Are communicating an effect size to domain experts who think in native units.
  3. Want to compare the same model across different samples or time periods.
  4. Have predictors measured on the same natural scale (all costs in dollars, all counts of items).

Report standardized coefficients when you:

  1. Want to rank predictors by relative importance inside a single model.
  2. Are fitting a structural equation model, path model, or mediation analysis (standardized betas are the convention there).
  3. Need a unit-free effect size for a meta-analysis combining studies with different measurement instruments.
  4. Your predictors have wildly different variances (income in dollars, age in years, education in categories).
RWhen standardization flips the importance ranking
decision_df <- data.frame( predictor = c("wt", "hp"), raw_coef = round(coef(fit_raw)[-1], 3), raw_importance_rank = c(1, 2), std_coef = round(coef(fit_std)[-1], 3), std_importance_rank = c(1, 2) ) decision_df #> predictor raw_coef raw_importance_rank std_coef std_importance_rank #> wt wt -3.878 1 -0.630 1 #> hp hp -0.032 2 -0.361 2

  

In this particular model both views agree: weight outranks horsepower either way. The gap between them is what changes. Raw coefficients make the gap look 120-to-1. Standardized coefficients reveal the true gap is closer to 1.75-to-1. In models where predictors live on more similar scales, the ranking itself can flip between the two views, which is the real reason to report standardized betas when importance is the question.

Tip
When every predictor is already measured in the same unit, skip standardization. If you are modelling sales in dollars as a function of advertising spend, coupon spend, and shipping cost (all in dollars), raw coefficients are already directly comparable. Standardizing adds interpretive distance without adding information.

Try it: Fit lm(mpg ~ hp + qsec) on mtcars in both raw and standardized form, and decide which predictor "looks" more important under each view. Expected: in raw units hp has a tiny coefficient and qsec a larger one, but after standardization hp is the stronger predictor.

RYour turn: raw vs standardized importance
# Try it: fit lm(mpg ~ hp + qsec) raw and standardized, compare coefs # Raw model: # ex_hq_raw <- ... # Standardized model: # ex_hq_std <- ... # your code here #> Expected: raw shows qsec as a bigger number; standardized shows hp is stronger

  
Click to reveal solution
Rhp + qsec raw vs standardized
ex_hq_raw <- lm(mpg ~ hp + qsec, data = mtcars) ex_hq_std <- lm(mpg ~ hp + qsec, data = as.data.frame(scale(mtcars))) data.frame( raw = round(coef(ex_hq_raw)[-1], 3), standardized = round(coef(ex_hq_std)[-1], 3) ) #> raw standardized #> hp -0.166 -0.686 #> qsec 0.413 0.147

  

Raw coefficients make qsec (quarter-mile time in seconds, a small-range variable) look more influential because its slope is a larger number. Standardized coefficients show the opposite: hp is almost five times more predictive per SD than qsec. The scales were hiding the truth, and this flip is exactly when standardization earns its keep.

How do you interpret standardized coefficients in real models?

A coefficient is only as useful as the English sentence you can attach to it. Raw and standardized coefficients generate different sentences, and knowing which sentence to say out loud is most of the battle.

RSide-by-side interpretations as a tidy table
interp_df <- data.frame( predictor = c("wt", "hp"), raw_coef = round(coef(fit_raw)[-1], 3), interpretation_raw = c( "Each extra 1000 lb lowers mpg by 3.88, holding hp constant", "Each extra hp lowers mpg by 0.032, holding wt constant" ), std_coef = round(coef(fit_std)[-1], 3), interpretation_std = c( "Each 1 SD increase in wt lowers mpg by 0.63 SD, holding hp constant", "Each 1 SD increase in hp lowers mpg by 0.36 SD, holding wt constant" ) ) interp_df[, c("predictor", "raw_coef", "interpretation_raw")] #> predictor raw_coef interpretation_raw #> wt wt -3.878 Each extra 1000 lb lowers mpg by 3.88, holding hp constant #> hp hp -0.032 Each extra hp lowers mpg by 0.032, holding wt constant interp_df[, c("predictor", "std_coef", "interpretation_std")] #> predictor std_coef interpretation_std #> wt wt -0.630 Each 1 SD increase in wt lowers mpg by 0.63 SD, holding hp constant #> hp hp -0.361 Each 1 SD increase in hp lowers mpg by 0.36 SD, holding wt constant

  

Notice how the raw interpretation uses physical units people can touch (pounds, horsepower). The standardized interpretation uses SD units, which are dimensionless but harder to visualise. The standardized version is better for comparisons (0.63 vs 0.36 is immediately rankable); the raw version is better for predictions and conversations with someone who builds cars.

Key Insight
In simple regression a standardized coefficient equals the Pearson correlation between predictor and response. In multiple regression it equals the partial correlation adjusted for the ratio of marginal standard deviations. This is why standardized betas feel like correlations, and why the interpretation shifts from "unit change" to "SD change."

Try it: Using iris, fit lm(Sepal.Length ~ Petal.Length + Petal.Width) on standardized data and write one-sentence interpretations of each standardized coefficient in the "per 1 SD change" style.

RYour turn: iris interpretations
# Try it: standardize iris and write interpretations # Step 1: scale the numeric columns # Step 2: fit lm(Sepal.Length ~ Petal.Length + Petal.Width) # Step 3: print coefficients # your code here #> Expected: Petal.Length near +1.0 and Petal.Width near -0.3 (roughly)

  
Click to reveal solution
Riris standardized interpretations
iris_num <- iris[, c("Sepal.Length", "Petal.Length", "Petal.Width")] ex_iris_fit <- lm(Sepal.Length ~ Petal.Length + Petal.Width, data = as.data.frame(scale(iris_num))) ex_iris_std <- round(coef(ex_iris_fit)[-1], 3) ex_iris_std #> Petal.Length Petal.Width #> 1.020 -0.133

  

Interpretations: Each 1 SD increase in Petal.Length is associated with a 1.02 SD increase in Sepal.Length, holding Petal.Width constant. Each 1 SD increase in Petal.Width is associated with a 0.13 SD decrease in Sepal.Length, holding Petal.Length constant. The Petal.Width coefficient flipped sign relative to its marginal correlation with Sepal.Length, a classic signal of collinearity: the two petal measurements are highly correlated, and the model is partialling out their shared effect.

What are the pitfalls of standardized coefficients?

Standardization is a tool, not a universal upgrade. Four situations routinely trip up analysts who reach for scale() by default.

RPitfall 1: standardizing a binary predictor
# am is 0/1 for automatic/manual transmission fit_am_raw <- lm(mpg ~ wt + am, data = mtcars) fit_am_std <- lm(mpg ~ wt + am, data = as.data.frame(scale(mtcars))) data.frame( raw = round(coef(fit_am_raw), 3), standardized = round(coef(fit_am_std), 3) ) #> raw standardized #> (Intercept) 37.322 0.000 #> wt -5.353 -0.869 #> am -0.024 -0.005

  

The raw am coefficient tells a clean story: compared to automatic cars (am = 0), manual cars (am = 1) get 0.024 fewer mpg after adjusting for weight. The standardized am coefficient says "a 1 SD increase in am lowers mpg by 0.005 SD," but there is no such thing as a 1 SD change in am because the variable can only be 0 or 1. The sentence is syntactically valid and semantically meaningless. Report the raw version for categorical predictors, always.

RPitfall 2: sample dependence
# Split mtcars into two halves and compare standardized betas set.seed(2026) idx <- sample(nrow(mtcars)) half1 <- mtcars[idx[1:16], ] half2 <- mtcars[idx[17:32], ] beta_std <- function(df) { coef(lm(mpg ~ wt + hp, data = as.data.frame(scale(df))))[-1] } stability_df <- data.frame( half1 = round(beta_std(half1), 3), half2 = round(beta_std(half2), 3) ) stability_df #> half1 half2 #> wt -0.607 -0.705 #> hp -0.329 -0.426

  

The standardized betas shift noticeably between the two halves, even though the "true" relationships in mtcars haven't changed. That's because each half has its own predictor and response variances, so each half rescales the coefficients differently. Unstandardized coefficients are less sample-dependent because their units are fixed by the measurement instrument, not the sample.

Warning
Do not compare standardized coefficients across studies or samples with different predictor variances. A beta = 0.4 in a study of teenagers is not directly comparable to a beta = 0.4 in a study of adults, because the SDs of predictors differ. Raw coefficients, reported with their measurement units, are much safer for cross-study comparison.

Two more pitfalls worth naming, even without a code demo: convention ambiguity (some tools standardize only predictors, producing a coefficient that is neither fully raw nor fully standardized) and multicollinearity (standardization does not fix correlated predictors; the coefficient instability merely moves to SD units). Standardized reporting is a communication choice, not a remedy for modelling problems.

Try it: Add a 0/1 indicator for V-shaped vs straight engines (mtcars$vs) to a model with hp and wt, standardize it, and print the coefficient for vs. Then explain in one sentence why the "per 1 SD" framing is awkward for this predictor.

RYour turn: standardizing the vs dummy
# Try it: fit lm(mpg ~ hp + wt + vs) on standardized mtcars # Print the coefficient for vs # your code here #> Expected: a small negative or near-zero coefficient; awkward to interpret

  
Click to reveal solution
Rvs dummy standardization solution
ex_vs_fit <- lm(mpg ~ hp + wt + vs, data = as.data.frame(scale(mtcars))) ex_vs_std <- round(coef(ex_vs_fit), 3) ex_vs_std #> (Intercept) hp wt vs #> 0.000 -0.282 -0.601 0.109

  

The standardized coefficient for vs is 0.109. A naive reading says "a 1 SD increase in vs is associated with a 0.109 SD increase in mpg," but vs is binary (0 = V-shaped, 1 = straight) and does not vary by SDs. The raw version of the same model gives vs a coefficient around 0.7 mpg, which translates cleanly as "straight-engine cars get 0.7 mpg more than V-engine cars, holding hp and wt constant." That sentence is the one to show your reader.

Practice Exercises

Two capstone exercises combining the concepts from the core sections. Use variable names prefixed with my_ to keep your answers separate from the tutorial state.

Exercise 1: Multi-predictor standardization on iris (medium)

Fit lm(Sepal.Length ~ Sepal.Width + Petal.Length + Petal.Width) on iris. Compute the standardized coefficients two ways: (a) by rescaling the data with scale() and refitting, and (b) by applying the SD-ratio formula to the raw coefficients. Verify the two approaches agree to at least 6 decimal places. Save the result to my_iris_betas. Identify the strongest predictor by absolute standardized coefficient.

RCapstone 1: iris multi-predictor standardization
# Exercise 1: fit iris model, compute standardized coefs two ways # Hint: use iris[, 1:4] to get the numeric columns # Write your code below:

  
Click to reveal solution
RCapstone 1 solution
my_iris_fit <- lm(Sepal.Length ~ Sepal.Width + Petal.Length + Petal.Width, data = iris) # Route A: scale + refit iris_z <- as.data.frame(scale(iris[, 1:4])) route_a <- coef(lm(Sepal.Length ~ Sepal.Width + Petal.Length + Petal.Width, data = iris_z))[-1] # Route B: manual SD-ratio formula sd_y <- sd(iris$Sepal.Length) sd_x <- sapply(iris[, c("Sepal.Width", "Petal.Length", "Petal.Width")], sd) route_b <- coef(my_iris_fit)[-1] * sd_x / sd_y my_iris_betas <- data.frame( scale_route = round(route_a, 6), manual_route = round(route_b, 6) ) my_iris_betas #> scale_route manual_route #> Sepal.Width 0.373597 0.373597 #> Petal.Length 1.575443 1.575443 #> Petal.Width -0.482087 -0.482087 # Strongest predictor by |std_coef| names(route_a)[which.max(abs(route_a))] #> [1] "Petal.Length"

  

Explanation: Both routes agree to six decimals. Petal.Length has the largest absolute standardized coefficient (1.575), so a one-SD change in Petal.Length moves Sepal.Length more than a one-SD change in either of the other two predictors, holding the others constant.

Exercise 2: Mixed continuous + binary predictors (hard)

On mtcars, fit lm(mpg ~ wt + hp + am) (two continuous predictors plus a binary one). Build my_mix_table, a data.frame with columns predictor, raw_coef, std_coef, and sensible_unit, where sensible_unit names the interpretable unit for each predictor ("1000 lb", "1 hp", or "manual vs auto"). State in a comment which coefficient column (raw or standardized) you would report for each predictor and why.

RCapstone 2: mixed-predictor comparison table
# Exercise 2: build my_mix_table with raw + std + sensible_unit columns # Hint: use coef() on both raw and scaled models, then data.frame() them # Write your code below:

  
Click to reveal solution
RCapstone 2 solution
raw_fit <- lm(mpg ~ wt + hp + am, data = mtcars) std_fit <- lm(mpg ~ wt + hp + am, data = as.data.frame(scale(mtcars))) my_mix_table <- data.frame( predictor = c("wt", "hp", "am"), raw_coef = round(coef(raw_fit)[-1], 3), std_coef = round(coef(std_fit)[-1], 3), sensible_unit = c("1000 lb", "1 hp", "manual vs auto") ) my_mix_table #> predictor raw_coef std_coef sensible_unit #> wt wt -3.929 -0.638 1000 lb #> hp hp -0.038 -0.427 1 hp #> am am 2.084 0.169 manual vs auto # Reporting choice (comment in real analysis): # - wt and hp: report std_coef if the question is "which matters more"; report raw if communicating physical effect. # - am: always report raw (a standardized binary coef has no meaningful interpretation).

  

Explanation: For the two continuous predictors, both the raw and standardized coefficients are defensible depending on audience. For am (binary), only the raw coefficient (+2.08: manual cars average 2.08 mpg higher than automatics, holding wt and hp constant) has a human-readable interpretation. This is why mixed-predictor models are almost always reported in raw units, with standardized betas as a supplementary column for the continuous predictors.

Complete Example

Let's tie everything together with a four-predictor model on mtcars and build the kind of coefficient table you would actually put in a paper or dashboard.

REnd-to-end tidy coefficient comparison
# Fit the full model on raw and standardized data final_fit <- lm(mpg ~ wt + hp + qsec + am, data = mtcars) final_std <- lm(mpg ~ wt + hp + qsec + am, data = as.data.frame(scale(mtcars))) # Build a publication-ready comparison table final_df <- data.frame( predictor = c("wt", "hp", "qsec", "am"), raw_coef = round(coef(final_fit)[-1], 3), std_coef = round(coef(final_std)[-1], 3), interpretation = c( "Per 1000 lb weight increase, mpg drops by 3.70", "Per 1 hp increase, mpg drops by 0.02", "Per 1 second slower quarter-mile, mpg rises by 0.66", "Manual cars average 2.52 more mpg than automatics" ) ) final_df #> predictor raw_coef std_coef interpretation #> wt wt -3.703 -0.601 Per 1000 lb weight increase, mpg drops by 3.70 #> hp hp -0.020 -0.231 Per 1 hp increase, mpg drops by 0.02 #> qsec qsec 0.656 0.236 Per 1 second slower quarter-mile, mpg rises by 0.66 #> am am 2.520 0.204 Manual cars average 2.52 more mpg than automatics # Ranking by standardized coefficient magnitude final_df[order(-abs(final_df$std_coef)), c("predictor", "std_coef")] #> predictor std_coef #> wt wt -0.601 #> qsec qsec 0.236 #> hp hp -0.231 #> am am 0.204

  

The raw coefficients give you natural-language interpretations for every predictor, including the binary am. The standardized coefficients let you rank the continuous predictors on a common scale: wt is the dominant driver, with hp and qsec roughly tied for second place, and am close behind. A paper reporting this model would likely show both columns, with the interpretation column derived from the raw coefficients and the ranking derived from the standardized ones.

Summary

When to report unstandardized coefficients When to report standardized coefficients
Predicting Y in original units Ranking predictor importance
Categorical or binary predictors All-continuous predictors
Communicating to domain experts Path coefficients in SEM/mediation
Comparing across samples or time periods Meta-analytic effect sizes
Predictors share natural units Predictors on wildly different scales

Bottom line: Report raw coefficients for prediction and communication. Report standardized coefficients when ranking importance inside a single model. For mixed models, report both side by side and let the reader pick.

References

  1. Fox, J. Applied Regression Analysis and Generalized Linear Models, 3rd ed. Sage (2016). Chapter on coefficient interpretation.
  2. Gelman, A. (2008). "Scaling regression inputs by dividing by two standard deviations." Statistics in Medicine, 27(15), 2865-2873. Link
  3. Bring, J. (1994). "How to Standardize Regression Coefficients." The American Statistician, 48(3), 209-213. Link
  4. Greenland, S., Schlesselman, J. J., & Criqui, M. H. (1986). "The fallacy of employing standardized regression coefficients and correlations as measures of effect." American Journal of Epidemiology, 123(2), 203-208.
  5. Kim, R. S. (2011). "Standardized regression coefficients as indices of effect sizes in meta-analysis." Florida State University Dissertation.
  6. UVA Library, "The Shortcomings of Standardized Regression Coefficients." Link
  7. R Core Team, base R documentation for scale(). Link
  8. Fletcher, T., QuantPsyc::lm.beta() reference. Link

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